If f={(1,3),(2,5),(3,7)} and g={(3,10),(4,13),(5,16),(6,19),(7,22)}, then g∘f is

f(1)=3g(f(1))=g(3)=10f(2)=5g(f(2))=g(5)=16 f3=7gf3=g7=22gof={(1,10),(2,16),(3,22)}

If f={(1,3),(2,5),(3,7)} and g={(3,10),(4,13),(5,16),(6,19),(7,22)}, then g∘f is

f(1)=3g(f(1))=g(3)=10f(2)=5g(f(2))=g(5)=16 f3=7gf3=g7=22gof={(1,10),(2,16),(3,22)}

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If $f = {(1, 3), (2, 5), (3, 7)} and g = {(3, 10), (4, 13), (5, 16), (6, 19), (7, 22)}, then g \circ f$ is

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${(1, 10), (2, 16), (3, 22)}$

${(3, 3), (5, 5), (7, 7)}$

${(1, 10), (2, 13), (3, 5)}$

${(1, 16), (2, 10), (3, 22)}$

answer is A.

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Detailed Solution

$\begin{array}{l} f (1) = 3 \\ g (f (1)) = g (3) = 10 \\ f (2) = 5 \\ g (f (2)) = g (5) = 16 \\ f (3) = 7 \\ g (f (3)) = g (7) = 22 \end{array}$

$g o f = {(1, 10), (2, 16), (3, 22)}$

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If f={(1,3),(2,5),(3,7)} and g={(3,10),(4,13),(5,16),(6,19),(7,22)}, then g∘f is

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If $f = {(1, 3), (2, 5), (3, 7)} and g = {(3, 10), (4, 13), (5, 16), (6, 19), (7, 22)}, then g \circ f$ is