Q.

 If f:NR be a function such that f(x+y)=2f(x)f(y) for natural numbers x and y. If f(1)=2, then the value of α for whichk=110 f(α+k)=51232201 holds, is 

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a

2

b

6

c

3

d

4

answer is C.

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Detailed Solution

f:NR,f(x+y)=2f(x)f(y)..(1) f(1)=2, k=110f(α+k)=2f(α)k=110f(k)=2f(α)(f(1)+f(2)++f(10))..(2)  From (1)f(2)=2f2(1)=23f(3)=2f(2)f(1)=25 f(10)=29f10(1)=219 f(α)=22α1;αN
From  (2) k=110f(α+k)=222α12+23+25+..+219
51232201=22α222013  Hence α=4

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 If f:N→R be a function such that f(x+y)=2f(x)f(y) for natural numbers x and y. If f(1)=2, then the value of α for which∑k=110  f(α+k)=5123220−1 holds, is