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Q.

Iff:RR  definedbyf(x)=x  for  x2  andf(x)=5x2  for  x<2,thenfis

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a

One – one onto

b

Onto only

c

Neither one – one nor onto

d

One – one

answer is B.

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Detailed Solution

f(x)={xfor  x25x2forx<2If  x=2,  f(x)=xf(2)=2If  x=45f(45)=5(45)22  f(2)=f(45)Differentelements  havesameimage  f  isnot  oneone

If  x2  then  f(x)=x  f(x)2If  x<2  thenf(x)=5x2  5x<105x2<102f(x)<8  Range=(,  8)[2,  )  =  (,  )=  codomain  f  is  onto

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