If $f:R\to R,g:R\to R$ be twice differentiable function satisfying  $f^{11}\left(x\right)=g^{11}\left(x\right),2f^1\left(1\right)=g^1\left(1\right)=4$ and $3f\left(2\right)=g\left(2\right)=9$ then  $f\left(4\right)-g\left(4\right)=$

$\begin{array}{l}{f}^{11}\left(x\right)-g^{11}\left(x\right)=0\Rightarrow f^1\left(x\right)-g^1\left(x\right)=c\\ \Rightarrow f^1\left(1\right)-g^1\left(1\right)=c\Rightarrow 2-4=c\\ \Rightarrow f^1\left(x\right)-g^1\left(x\right)=-2\Rightarrow f\left(x\right)-g\left(x\right)=-2x+d\\ \Rightarrow f\left(2\right)-g\left(2\right)=-4+d\\ \Rightarrow 3-9=-4+d\Rightarrow d=-2\Rightarrow f\left(x\right)-g\left(x\right)-2x-2\\ \Rightarrow f\left(4\right)-g\left(4\right)=-10\end{array}$