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Q.

If f x   and g x   are differentiable functions in 0,1   such that f 0 =2,f 1 =6,g 0 =0,g 1 =2  , then there exists 0<c<1   such that

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a

f'c=g'c 

b

f' c =g' c  

c

f' c =2g' c  

d

2f' c =g' c   

answer is C.

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Detailed Solution

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 Let F(x)=f(x)2g(x), F(0)=f(0)2g(0)=2, F(1)=f(1)2g(1)=2 
 F(x) satisfies the conditions for Rolle’s theorem and there exist c, such that 
F(c)=0 or f(c)2g(c)=0 for 0<c<1 

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