$\text{ If }f\left(x\right)=\frac{1}{x^2-17x+66}\text{ then }f\left(\frac{2}{x-2}\right)\text{ is discontinuous at }x\text{ is equal to }$

$\text{ Let }t=\frac{2}{x-2}\text{ is discontinuous at }x=2$

$f\left(t\right)=\frac{1}{t^2-17t+66}=\frac{1}{(t-11)(t-6)}\text{ is discontinuous at }\mathrm{t}=6,11$

$\therefore \frac{2}{x-2}=6,11\Rightarrow x=\frac{7}{3},\frac{24}{11}$