If f(x)=3x+25x−3 , then

f(x)=3x+25x−3=y3x+2=(5x−3)y3x+2=5xy−3y3y+2=5xy−3x3y+2=x(5y−3)x=3y+25y−3⇒f−1(y)=3y+25y−3f−1(x)=3x+25x−3=f(x)

If f(x)=3x+25x−3 , then

f(x)=3x+25x−3=y3x+2=(5x−3)y3x+2=5xy−3y3y+2=5xy−3x3y+2=x(5y−3)x=3y+25y−3⇒f−1(y)=3y+25y−3f−1(x)=3x+25x−3=f(x)

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If $f (x) = \frac{3 x + 2}{5 x - 3}$ , then

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$f^{- 1} (x) = f (x)$

$f^{- 1} (x) = - f (x)$

$f^{- 1} (x) = - \frac{1}{19} f (x)$

$(f o f) (x) = - x$

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$f (x) = \frac{3 x + 2}{5 x - 3} = y$

$3 x + 2 = (5 x - 3) y$

$3 x + 2 = 5 x y - 3 y$

$\begin{array}{l} 3 y + 2 = 5 x y - 3 x \\ 3 y + 2 = x (5 y - 3) \\ x = \frac{3 y + 2}{5 y - 3} \Rightarrow f^{- 1} (y) = \frac{3 y + 2}{5 y - 3} \end{array}$

$f^{- 1} (x) = \frac{3 x + 2}{5 x - 3} = f (x)$

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If f(x)=3x+25x−3 , then

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If $f (x) = \frac{3 x + 2}{5 x - 3}$ , then