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If $f (x + 3) = x^{2} + x - 6$ , then $f (x) =$

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$x (x - 5)$

$x (x + 5)$

$x (x - 6)$

$x (x - 7)$

answer is A.

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Detailed Solution

$\begin{array}{l} f (x + 3) = x^{2} + x - 6 \\ f (x + 3 - 3) = {(x - 3)}^{2} + (x - 3) - 6 \\ = x^{2} - 5 x = x (x - 5) \end{array}$

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