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Q.

If f(x)=4xx2,xR, then f(a+1)f(a1) is equal to

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a

2(4a)

b

4(2a)

c

2(4+a)

d

4(2+a)

answer is B.

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Detailed Solution

4(a+1)(a+1)2[4(a1)(a1)2]

=4a+4a212a[4a4a21+2a]

=4a+4a212a4a+4+a2+12a

=84a

=4(2a)

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