If f(x)=cosec−1x+1xthen range of fx is equal to

x+1x≥2, for x>0 and x+1x≤−2 for x<0.

If f(x)=cosec−1x+1xthen range of fx is equal to

x+1x≥2, for x>0 and x+1x≤−2 for x<0.

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If $f (x) = {cosec}^{- 1} (x + \frac{1}{x})$ then range of $f (x)$ is equal to

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$(\frac{- π}{6}, \frac{π}{6}) - \{0\}$

$[\frac{- π}{6}, \frac{π}{6}]$

$(\frac{- π}{6}, \frac{π}{6})$

$[\frac{- π}{6}, 0) \cup (0, \frac{π}{6}]$

answer is D.

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$x + \frac{1}{x} \geq 2, for x > 0 and x + \frac{1}{x} \leq - 2 for x < 0 .$

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If f(x)=cosec−1x+1xthen range of fx is equal to

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If $f (x) = {cosec}^{- 1} (x + \frac{1}{x})$ then range of $f (x)$ is equal to