$$\begin{gathered} \mathrm{If} \mathrm{f}\left(\mathrm{x}\right)=\frac{\cos \mathrm{x}-\sqrt{3} \mathrm{sinx}}{\cos 3\mathrm{x}}, \mathrm{x}\ne \frac{\mathrm{\pi }}{6} \mathrm{is} \mathrm{continuous} \mathrm{on} \\ \left[0, \frac{\mathrm{\pi }}{2}\right], \mathrm{then} \mathrm{f}\left(\frac{\mathrm{\pi }}{6}\right)= \end{gathered}$$

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