$$\begin{gathered} \mathrm{If} \mathrm{f}\left(\mathrm{x}\right)=\frac{\left({\mathrm{e}}^{\mathrm{kx}}-1\right)\sin {\mathrm{k}}^2\mathrm{x}}{4{\mathrm{x}}^2}, \mathrm{x}\ne 0, \\ \mathrm{f}\left(0\right)=16 \mathrm{is} \mathrm{continuous} \mathrm{at} \mathrm{x}=0 \mathrm{then} \mathrm{k}= \end{gathered}$$

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