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If f(x)=g(x)+g(-x)2+2h(x)+h(-x)-1,where g and h are differentiable functions then ⨍ '(0)=

 

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detailed solution

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The given function is f (x)=g(x)+g(-x)2+2h(x)+h(-x)-1,

This can be written as 

fx=gx+g-x2+2hx+h-x

Differentiate both sides

f'x=g'x-g'-x2+2h'x-h'-x

Substitute x=0

f'0=0


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