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Q.

 Iffxsatisfies the relationf5x-3y2=5fx-3fy2x,yR, andf0=3andf'0=2, then the period of sin(f(x)) is

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a

3π

b

2π

c

4π

d

π

answer is B.

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Detailed Solution

Givenf5x-3y2=5fx-3fy2orf5x-3y5-3=5fx-3fy5-3

which satisfies section formula for abscissa on L.H.S. and for ordinate on R.H.S. Hence, f(x) must be the linear function 

(as only straight line satisfies such section formula).

Hence,fx=ax+bButf0=3orb=3,f'0=2ora=2.Thus,fx=2x+3orPeriodofsinfx=sin2x+3isπ.

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