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Q.

If f(x)=x2−2x+4 then the set of values of x satisfying f(x−1)=f(x+1) is

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a

{1}

b

{-1, 1}

c

{-1}

d

{1,2}

answer is C.

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Detailed Solution

f(x−1)=f(x+1)⇒(x−1)2−2(x−1)+4=(x+1)2−2(x+1)+4

⇒x2−2x+1−2x+2+4=x2+2x+1−2x−2+4⇒4x=4⇒x=1

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