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Q.

If ω is a complex cube root of unity, then cos(1ω)1ω2+(2ω)2ω2+(3ω)3ω2+(4ω)4ω2

+(5ω)5ω22π75 equals

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a

0

b

1

c

-1

d

12

answer is B.

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Detailed Solution

(1ω)1ω2=(1ω)(2+ω)1+ω=ω2=2+1=3

Similarly, we get (2ω)2ω2=7

(3ω)3ω2=13(4ω)4ω2=21(5ω)5ω2=31

So cos(1ω)1ω2+.+(5ω)5ω22π75

=cos[3+7+13+21+31]2π75=cos{2π}=1

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