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Q.

If 'ω' is a cube root of unity, then Δ=x+1ωω2ωx+ω21ω21x+ω=

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a

x3+1

b

x3+ω

c

x3+ω2

d

x3

answer is D.

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Detailed Solution

C1C1+C2+C3

Δ=|xωω2xx+ω21x1x+ω|=x|1ωω21x+ω2111x+ω|

R2R2R1,R3R3R1

Δ=x|1ωω20x+ω2ω1ω201ωx+ωω2|

=x[(x+ω2ω)(x+ωω2)(1ω2)(1ω)]=x3

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