If $' θ'$ is not an integral multiple of 180°, then $s e c^{2} θ - t a n^{2} θ =$

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$- 1$

answer is B.

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Detailed Solution

As per trigonometric identity 2

$s e c^{2} θ - t a n^{2} θ = \frac{1}{\cos^{2} θ} - \frac{\sin^{2} θ}{\cos^{2} θ} = \frac{1 - \sin^{2} θ}{\cos^{2} θ} = \frac{\cos^{2} θ}{\cos^{2} θ} = 1$

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