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Q.

If $\log_{10} 2 = 0.3010$ , then the position of first significant figure in $16^{- 25}$ is

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a

61

b

41

c

51

d

31

answer is C.

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Detailed Solution

$k = 16^{- 25}$

$\log k = 16^{- 25}$

$\log k = - 25 \log 2^{4} = - 100 \log 2$

$\log k = - 100 \times 0.3010$

$= - 30.1$

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