If ${\log }_{10}2731=3.4364$, then the number of digits in ${\left(27.31\right)}^{100}$is

Given ${\log }_{10}2731=3.4364$

Now ${\log }_{10}{\left(27.31\right)}^{100}=100{\log }_{10}27.31$

$=100\left(1.4364\right)$

$=143.64$

Number of digits in ${\left(27.31\right)}^{100}=144$