Q.

If  log103=0.4771, then the number of digits in the integral part of (3)25 is

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a

2

b

8

c

6

d

3

answer is C.

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Detailed Solution

Given log103=0.4771

Take x=(3)25=3252

Now log10x=log103252

=252log103

=252(0.4771)

=12.5(0.4771)

=5.96375

Number of digits in the integral part  of (3)25=6

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