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Q.

If log10x  dx=K.xlogf(x)+c, then K,f(x)=

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a

loge10,xe

b

log10e,ex

c

log210,xe

d

log10e,xe

answer is D.

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Detailed Solution

I=log10x  dx

=log10elogex  dx

=log10e[xlogxx.1xdx]+c

=log10e[xlogxx]+c

=log10e.xlog(xe)+c

K=log10e,f(x)=xe

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If ∫log10x  dx=K.xlogf(x)+c, then K,f(x)=