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Q.

If $\log_{2} x + \log_{8} x + \log_{64} + x = 3$ , then $x =$

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a

2

b

8

c

4

d

16

answer is B.

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Detailed Solution

$\log_{2} x + \log_{8} x + \log_{64} x = 3$

$\log_{2} x (\frac{9}{6}) = 3$

$\log_{2} x (\frac{3}{2}) = 3$

$\log_{2} x = 2$

$x = 2^{2} = 4$

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