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Q.

If log3=0.4771 then log3+log15=

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a

2.1492

b

1.2143

c

2.103

d

1.65     

answer is D.

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Detailed Solution

log3+log15=log3+log(3×5)=log3+log3+log5=2log3+log5(log5=0.698)=0.9542+0.698=1.65

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