Q.

If λm∞12Zn2+=52.8Scm2mol−1, and Λm∞Zn3Fe(CN)62=922.8Scm2mol−1  The Λm∞Fe(CN)63− will be 

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a

101 S cm2 mol−1

b

202 S cm2 mol−1

c

303 S cm2 mol−1

d

404 S cm2 mol−1

answer is C.

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Detailed Solution

ΛmZn3Fe(CN)62=3λmZn2++2λmFe(CN)63− =3×2λm12Zn2++2λmFe(CN)63− or λmFe(CN)63−=12ΛmZn3Fe(CN)62−6λm12Zn2+=12[922.8−6×52.8]Scm2mol−1=303Scm2mol−1

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