Q.

If λm12Zn2+=52.8Scm2mol1, and ΛmZn3Fe(CN)62=922.8Scm2mol1  The ΛmFe(CN)63 will be 

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a

101 S cm2 mol1

b

202 S cm2 mol1

c

303 S cm2 mol1

d

404 S cm2 mol1

answer is C.

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Detailed Solution

ΛmZn3Fe(CN)62=3λmZn2++2λmFe(CN)63 =3×2λm12Zn2++2λmFe(CN)63 or λmFe(CN)63=12ΛmZn3Fe(CN)626λm12Zn2+=12[922.86×52.8]Scm2mol1=303Scm2mol1

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