If m and M respectively denote the minimum and maximum of ⨍ (x)=(x-1)2+3 for x∈-3,1 then the ordered pair (m, M)=

fx=x-12+3 -3≤x≤1 fIx=2x-1for x>1 Increasing x<1 decreasing⇒f-3=16+3=19 ⇒f1=3m=Minimum=3m=Maximum=19

If m and M respectively denote the minimum and maximum of ⨍ (x)=(x-1)2+3 for x∈-3,1 then the ordered pair (m, M)=

fx=x-12+3 -3≤x≤1 fIx=2x-1for x>1 Increasing x<1 decreasing⇒f-3=16+3=19 ⇒f1=3m=Minimum=3m=Maximum=19

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If $m$ and $M$ respectively denote the minimum and maximum of ${⨍ (x)=(x-1)}^{2} +3$ for $x \in [- 3, 1]$ then the ordered pair $(m, M) =$

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$(- 3, 19)$

$(- 19, 3)$

$(- 19, - 3)$

$(3, 19)$

answer is B.

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Detailed Solution

$f (x) = {(x - 1)}^{2} + 3 - 3 \leq x \leq 1 f^{I} (x) = 2 (x - 1)$

$for x > 1 Increasing x < 1 decreasing$

$\Rightarrow f (- 3) = 16 + 3 = 19 \Rightarrow f (1) = 3$

m=Minimum=3

m=Maximum=19

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If m and M respectively denote the minimum and maximum of ⨍ (x)=(x-1)2+3 for x∈-3,1 then the ordered pair (m, M)=

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If $m$ and $M$ respectively denote the minimum and maximum of ${⨍ (x)=(x-1)}^{2} +3$ for $x \in [- 3, 1]$ then the ordered pair $(m, M) =$