Q.

If N2  gas is bubbled through water at 293 K. How many moles of  N2 gas would dissolve in 1 lit of water assume that N2 exerts. Partial pressure of 0.987 bar. Given that Henry’s law constant for N2 at 293 K is  76.48Kbar is______ ×104mol. (density of H2O1g/ml )

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answer is 7.

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Detailed Solution

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PN2=KH×  XN 2

XN2=0.98776.48×103=0.0129×103=1.29×105

XN2=nN2nH2O=1.29×105=nN255.5      nH2=71.595×104

 

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