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If $N_{2} + 3 H_{2} ⇌ 2 N H_{3}$ ...(I) and $N_{2} + 3 H_{2} ⇌ 2 N H_{3}$ .... (II) are in equilibrium at same temperature, then

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An Intiative by Sri Chaitanya

KC of I = KC of II

KC of I = KP of II

KP of II > KP of I

KC of I < KP of II

answer is A.

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Detailed Solution

$KC = \frac{[{NH}_{3}]^{2}}{[N_{2}] [H_{2}]^{3}}$

For equation (II),

$KC = \frac{[{NH}_{3}]^{2}}{[N_{2}] [H_{2}]^{3}}$

KC(I) =KC(II)

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