If $n\left(A\right)=4, n\left(B\right)=5$, then number of functions from $A \mathrm{to} B$such that the range contains exactly 3 elements is $k$, then the value of $\frac{k}{60}$ is

$$\begin{gathered} Given that n\left(A\right)=4,n\left(B\right)=5 \\ Now number of functions from A to B such that the range contains exactly 3 elements \\ k=5C_3\left(3^3-{3.2}^3+1\right) \\ k=360 \\ Now \frac{k}{60}=6 \end{gathered}$$