If ${Na}^{+}$ ion is larger than ${Mg}^{2 +}$ ion and $S^{2 -}$ ion is larger than ${Cl}^{-}$ ion, which of the following will be least soluble in water?

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$NaCl$

${Na}_{2} S$

${MgCl}_{2}$

$MgS$

answer is D.

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Detailed Solution

Solubility of a compound in water depends

Lattice energy
Hydration energy

When the hydration energy is more than the lattice energy the compound becomes soluble in water.

Lattice energy is directly proportional to the product of the charges on the cation and the anion and inversely proportional to the distance between the charges.

MgS has Mg²⁺ and S²⁻. The product of charges is the highest and so will be the lattice energy. Hence, MgS is the least soluble.

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