If $n$is the orbit number of the electron in a hydrogen atom, the correct statement among the following is:

In a hydrogen atom, the energy of electron in $n^{th}$ orbit is

$E_n=\frac{-13.6}{n^2}eV$

when n increases, energy of electron becomes less negative and hence increases.

Energy released during transition from $n= \infty \mathrm{to} n = 1$ (Lyman series) is 13.6 eV.

wavelength of the photon = $\frac{12400}{13.6}\simeq 911 \stackrel{\circ }{\mathrm{A}}$ 

It comes under UV region.