If  then the line  touches the circle ____

 
 
$$\begin{gathered} {(3\mathrm{l}+1)}^2=5\left({\mathrm{l}}^2+{\mathrm{m}}^2\right)\Rightarrow \frac{\left|\right(3\mathrm{l}+0\mathrm{m}+1\left)\right|}{\sqrt{{\mathrm{l}}^2+{\mathrm{m}}^2}}=\sqrt{5} \\ \mathrm{lx}+\mathrm{my}+1=0 \mathrm{touch} \mathrm{a} \mathrm{circle} \mathrm{with} \mathrm{centre} (3,0) \mathrm{and} \mathrm{radius}=\sqrt{5} \end{gathered}$$