If n(P−Q)=x+37, n(Q−P)=30+3x, n(P∪Q)=120+2x, n(P∩Q)=35 then x=

n(P∪Q)=n(P−Q)+n(Q−P)+n(P∩Q)⇒120+2x=x+37+30+3x+35⇒120−102=4x−2x⇒18=2x⇒x=9

If n(P−Q)=x+37, n(Q−P)=30+3x, n(P∪Q)=120+2x, n(P∩Q)=35 then x=

n(P∪Q)=n(P−Q)+n(Q−P)+n(P∩Q)⇒120+2x=x+37+30+3x+35⇒120−102=4x−2x⇒18=2x⇒x=9

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If $n (P - Q) = x + 37, n (Q - P) = 30 + 3 x, n (P \cup Q) = 120 + 2 x, n (P \cap Q) = 35$ then $x =$

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$\begin{array}{l} n (P \cup Q) = n (P - Q) + n (Q - P) + n (P \cap Q) \\ \Rightarrow 120 + 2 x = x + 37 + 30 + 3 x + 35 \\ \Rightarrow 120 - 102 = 4 x - 2 x \\ \Rightarrow 18 = 2 x \\ \Rightarrow x = 9 \end{array}$

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If n(P−Q)=x+37, n(Q−P)=30+3x, n(P∪Q)=120+2x, n(P∩Q)=35 then x=

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If $n (P - Q) = x + 37, n (Q - P) = 30 + 3 x, n (P \cup Q) = 120 + 2 x, n (P \cap Q) = 35$ then $x =$