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Q.

If OA = 2i + 2J + k, OB = 2i + 4 j + 4k

 and the length of the internal bisector of BOA of triangle AOB is k, then 9k2=

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An Intiative by Sri Chaitanya

a

225

b

136

c

712

d

20

answer is B.

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Detailed Solution

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OA=4+4+1=3    OB=4+16+16=6 OA:OB=3 : 6=1 : 2 OC=1(OB)+2(OA)3       =6i+8j+6k3 k=OC=36+64+363   9k2=136

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If OA = 2i + 2J + k, OB = 2i + 4 j + 4k and the length of the internal bisector of ∠BOA of triangle AOB is k, then 9k2=