If $\overline{OC}$ is the bisector of $\angle AOB$whose measure is $80°$, then $\angle AOC=$

Given $\overrightarrow{OC}$ is the bisector of $\angle AOB$

And given $\angle AOB=80°$

$\therefore \angle AOC = \angle BOC$

$\therefore \angle AOB=\angle AOC+\angle BOC$

$80°=2\angle AOC\left[\because \angle AOC=\angle BOC\right]$

$\angle AOC=40°$