If P(A)=0.25,P(B)=0.5,P(A∩B)=0.14 then P(A¯∩B¯)=

P(A∪B)=P(A)+P(B)−P(A∩B) = 0.25+0.5−0.14= 0.61 P(A¯∩B¯)=1−P(A∪B) =1−0.61=0.39

P(A∪B)=P(A)+P(B)−P(A∩B) = 0.25+0.5−0.14= 0.61 P(A¯∩B¯)=1−P(A∪B) =1−0.61=0.39

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$I f P (A) = 0.25, P (B) = 0.5, P (A \cap B) = 0.14 t h e n P (\bar{A} \cap \bar{B}) =$

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0.19

0.61

0.29

0.39

answer is B.

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$\begin{matrix} P (A \cup B) = P (A) + P (B) - P (A \cap B) \\ = 0.25 + 0.5 - 0.14 = 0.61 \end{matrix}$

$P (\bar{A} \cap \bar{B}) = 1 - P (A \cup B)$

= $1 - 0.61 = 0.39$

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