If P(A)=0.4,P(B)=0.5,P(C)=0.6,P(A∩B)=0.2,(B∩C)=0.3,(C∩A)=0.25P(A∩B∩C)=0.1 then P(A∪B∪C)=

P(A∪B∪C)=0.4+0.5+0.6−0.2−0.3−0.25+0.1=0.85

If P(A)=0.4,P(B)=0.5,P(C)=0.6,P(A∩B)=0.2,(B∩C)=0.3,(C∩A)=0.25P(A∩B∩C)=0.1 then P(A∪B∪C)=

P(A∪B∪C)=0.4+0.5+0.6−0.2−0.3−0.25+0.1=0.85

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If $P (A) = 0.4, P (B) = 0.5, P (C) = 0.6,$ $P (A \cap B) = 0.2, (B \cap C) = 0.3,$ $(C \cap A) = 0.25$
$P (A \cap B \cap C) = 0.1$ then $P (A \cup B \cup C) =$

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0.75

0.55

0.65

0.85

answer is B.

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$P (A \cup B \cup C) = 0.4 + 0.5 + 0.6 - 0.2 - 0.3 - 0.25 + 0.1$

$= 0.85$

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If P(A)=0.4,P(B)=0.5,P(C)=0.6,P(A∩B)=0.2,(B∩C)=0.3,(C∩A)=0.25P(A∩B∩C)=0.1 then P(A∪B∪C)=

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If $P (A) = 0.4, P (B) = 0.5, P (C) = 0.6,$ $P (A \cap B) = 0.2, (B \cap C) = 0.3,$ $(C \cap A) = 0.25$
$P (A \cap B \cap C) = 0.1$ then $P (A \cup B \cup C) =$