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Q.

If $P = \frac{A^{3}}{B^{5 / 2}}$ and $Δ A$ is absolute error in A and $Δ B$ is absolute error in B then absolute error $ΔP$ in P is :

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a

$ΔP = \pm (3 \frac{ΔA}{B} - \frac{5}{2} \frac{ΔB}{A}) P$

b

$ΔP = \pm (3 \frac{ΔA}{A} + \frac{5}{2} \frac{ΔB}{B}) P$

c

$ΔP = \pm (3 \frac{ΔA}{A} + \frac{5}{2} \frac{ΔB}{B})$

d

$ΔP = \pm (3 \frac{ΔA}{A} - \frac{5}{2} \frac{ΔB}{B}) P$

answer is A.

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Detailed Solution

$\frac{ΔP}{P} = \pm (3 \frac{ΔA}{A} + \frac{5}{2} \frac{ΔB}{B})$

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