If $P (A \cup B) = 0.65, P (A \cap B) = 0.15$ , then $P (\bar{A}) + P (\bar{B}) =$

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$0.8$

$0.2$

$1.2$

$0.6$

answer is A.

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Detailed Solution

$\begin{array}{l} P (A \cup B) = 0.65 \\ P (A \cap B) = 0.15 \\ P (\bar{A}) + P (\bar{B}) = 2 - [P (A \cup B) + P (A \cap B)] \\ = 2 - [0.65 + 0.15] \\ = 2 - 0.8 \\ = 1.2 \end{array}$

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