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Q.

If P=i+2j+6k, its direction cosines are ..

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a

141,241 and 641

b

341,841,741

c

141,241 and 641

d

1, 2 and 6

answer is B.

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Detailed Solution

P=i^+2j^+6k^;P^=P|P|=i^+2j^+6k^41

cosα=141;cosβ=241;cosγ=641.

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