If P→=i+2j+6k, its direction cosines are ..

P→=i^+2j^+6k^;P^=P→|P→|=i^+2j^+6k^41cos⁡α=141;cos⁡β=241;cos⁡γ=641.

If P→=i+2j+6k, its direction cosines are ..

P→=i^+2j^+6k^;P^=P→|P→|=i^+2j^+6k^41cos⁡α=141;cos⁡β=241;cos⁡γ=641.

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If $\vec{P} = i + 2 j + 6 k,$ its direction cosines are ..

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$\frac{1}{41}, \frac{2}{41} and \frac{6}{41}$

$\frac{3}{\sqrt{41}}, \frac{8}{\sqrt{41}}, \frac{7}{\sqrt{41}}$

$\frac{1}{\sqrt{41}}, \frac{2}{\sqrt{41}} and \frac{6}{\sqrt{41}}$

1, 2 and 6

answer is B.

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Detailed Solution

$\vec{P} = \hat{i} + 2 \hat{j} + 6 \hat{k}; \hat{P} = \frac{\vec{P}}{| \vec{P} |} = \frac{\hat{i} + 2 \hat{j} + 6 \hat{k}}{\sqrt{41}}$

$\cos α = \frac{1}{\sqrt{41}}; \cos β = \frac{2}{\sqrt{41}}; \cos γ = \frac{6}{\sqrt{41}}$ .

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If $\vec{P} = i + 2 j + 6 k,$ its direction cosines are ..