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Q.

If $P + Q = R$ and $P - Q = S$ , then $R^{2} + S^{2}$ is equal to

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a

$P^{2} + Q^{2}$

b

$2 (P^{2} - Q^{2})$

c

$2 (P^{2} + Q^{2})$

d

$4 P Q$

answer is B.

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Detailed Solution

$R^{2} = P^{2} + Q^{2} + 2 P Q \cos θ$

$S^{2} = P^{2} + Q^{2} - 2 P Q \cos θ$

$R^{2} + S^{2} = 2 (P^{2} + Q^{2})$

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