If P=x∈R:f(x)=0 and Q=x∈R:g(x)=0 then P∪Q is

f(x).g(x)=0⇒ eitherf(x)=0 or g(x)=0.

If P=x∈R:f(x)=0 and Q=x∈R:g(x)=0 then P∪Q is

f(x).g(x)=0⇒ eitherf(x)=0 or g(x)=0.

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If $P = \{x \in R : f (x) = 0\}$ and $Q = \{x \in R : g (x) = 0\}$ then $P \cup Q$ is

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$\{x \in R; {(f (x))}^{2} + {(g (x))}^{2} = 0\}$

$\{x \in R; x > 1\}$

$\{x \in R : f (x) + g (x) = 0\}$

$\{x \in R : f (x) . g (x) = 0\}$

answer is B.

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$f (x) . g (x) = 0 \Rightarrow either f (x) = 0 or g (x) = 0.$

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If P=x∈R:f(x)=0 and Q=x∈R:g(x)=0 then P∪Q is

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If $P = \{x \in R : f (x) = 0\}$ and $Q = \{x \in R : g (x) = 0\}$ then $P \cup Q$ is