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Q.

If qf is the free charge on the capacitor plates and qb is the bound charge on the dielectric slab of dielectric constant k placed between the capacitor plates, then the magnitude of bound charge qb can be expressed as :

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a

qb=qf(1−1k)

b

qb=qf(1−1k)

c

qb=qf(1+1k)

d

qb=qf(1+1k)

answer is B.

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Detailed Solution

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When a dielectric is inserted in a capacitor Due to free charge E→=E→0 only

After dielectric  E′=E0k

qB=qf(1−1k)

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