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If $S_{0}, S, S_{2}$ and $S_{3}$ are the solubilities of AgCl in water $0.01 M {CaCl}_{2}, 0.01 M NaCl$ and $0.05 M {AgNO}_{3}$ solutions, respectively, then

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$s_{0} > s_{2} > s_{3} > s_{1}$

$S_{0} > s_{2} > s_{1} > s_{3}$

$s_{0} > s_{1} = s_{2} > s_{3}$

$s_{0} > s_{1} > s_{2} > s_{3}$

answer is B.

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Detailed Solution

$s_{0} = \sqrt{K_{sp}}; s_{1} = K_{sp} / 0.02 M; s_{2} = K_{sp} / 0.01 M; s_{3} = K_{sp} / 0.05 M$ .Obviously $s_{0} > s_{2} > s_{1} > s_{3}$ .

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