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If Sin-1x2-y2x2+y2=log a then dydx=

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a
xy
b
yx
c
2y2x2+y22
d
2x2x2+y2

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detailed solution

Correct option is B

The given equation is Sin-1x2-y2x2+y2=log a

it implies that x2-y2x2+y2=sinloga

Differentiate both sides with respect to x

x2+y22x-2ydydx-x2-y22x+2ydydxx2+y22=0

dydx2yx2+y2+2yyx2-y2=2xx2+y2-2xx2-y2dydx=2xy22x2y =yx

Therefore, dydx=yx

 

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