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Q.

If $\sin^{- 1} (\sin x) = π - x$ , then x belongs to

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a

R

b

$[0, π]$

c

$[\frac{π}{2}, \frac{3 π}{2}]$

d

$[π, 2 π]$

answer is C.

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Detailed Solution

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$g i v e n \sin^{- 1} (\sin x) = π - x \Rightarrow \frac{- π}{2} < π - x < \frac{π}{2} \Rightarrow \frac{π}{2} < x < \frac{3 π}{2}$

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