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Q.

If sin1x+sin1wsin1y+sin1z=π2, then D=xN1yN2zN3wN4N1,N2,N3,N4N

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a

16 different D are possible

b

has a maximum value of 2

c

has a minimum value of –2

d

has a minimum value of 0

answer is A, C, D.

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Detailed Solution

sin1x+sin1w=sin1y+sin1z=πx=y=z=w=1 or x=y=z=w=1
Hence, the maximum value of xN1yN2zN3wN4=1111=2 and minimum value 1111=2
Also, there are 16 different determinants as each place value is either 1 or –1.

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