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Q.

If $\sin 3 α = 4 \sin α \sin (x + α) \sin (x - α)$ then general solution of x is

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a

$n π \pm \frac{π}{4}$

b

$n π \pm \frac{π}{6}$

c

$n π$

d

$n π \pm \frac{π}{3}$

answer is D.

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Detailed Solution

$\sin (A + B) \sin (A - B) = \sin^{2} A - \sin^{2} B$

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