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Q.

If $\sin θ + \cos θ = 1$ then $\sin 2 θ =$

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a

1

b

-1

c

1/2

d

0

answer is C.

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Detailed Solution

$\sin θ + \cos θ = 1$

On squaring both sides , we get

$\begin{matrix} \Rightarrow \sin^{2} θ + \cos^{2} θ + 2 \sin θ \cos θ = 1 \\ \Rightarrow 1 + \sin 2 θ = 1 \\ \Rightarrow \sin (2 θ) = 0 \end{matrix}$

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