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$If (\sin α + cosec α)^{2} + (\cos α + \sec α)^{2} = k + \tan^{2} α + \cot^{2} α then k =$

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answer is B.

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Detailed Solution

$L.H.S = \sin^{2} α + {cosec}^{2} α + 2 + \cos^{2} α + \sec^{2} α + 2 = 7 + \cot^{2} α + \tan^{2} α$
$∴ k = 7$

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